Here is the script:
Set wrdApp = CreateObject
("Word.Application")
wrdApp.documents.add
(xtempDrive$+"mydoc.doc")
wrdApp.Visible = True
' Add a new document
Set wrddoc =
wrdapp.Application.ActiveDocument
Set wrdSelection = wrdApp.Selection
Set range = wrdSelection.range
Set tables = wrdApp.Selection.tables.add
(range, 1,7)
Dim wdAdjustProportional As Integer
Dim wdAdjustNone As Integer
Dim wdAdjustFirstColumn As Integer
wdAdjustProportional = 1
wdAdjustNone = 0
wdAdjustFirstColumn = 2
wrdDoc.Tables(1).Columns(1).
SetWidth 1.18, wdAdjustProportional
wrdDoc.Tables(1).Columns(2).
SetWidth 0.02, wdAdjustProportional
wrdDoc.Tables(1).Columns(3).
SetWidth 2.5, wdAdjustProportional
wrdDoc.Tables(1).Columns(4).
SetWidth "0,02", wdAdjustProportional
wrdDoc.Tables(1).Columns(5).
SetWidth "1,3", wdAdjustProportional
wrdDoc.Tables(1).Columns(6).
SetWidth "0,02", wdAdjustProportional
wrdDoc.Tables(1).Columns(7).
SetWidth "1,12", wdAdjustProportional
wrdDoc.Tables(1).Rows.Alignment 1
' wrdDoc.Tables(1).Rows.SetLeftIndent -21.6
But LotusScript gives me this error, "Value out of range" when it hits the first "wrdDoc.Tables(x).Columns(x).SetWidth "xxxx", wdAdjustProportional."
Which is incorrect? Thank you very much.
I would also check the Microsoft sites and forums.
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This was first published in October 2004